UPES Dehradun BA Admissions 2026
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How to Calculate CUET Score Out of 200: Students can apply for their desired college by calculating their CUET 2024 scores. The scores obtained in the Common University Entrance Test will be calculated with the use of CUET 2024 marks vs percentile method. In this article, students can learn how the CUET result 2024 will be calculated from percentile into marks.
The CUET 2024 was held for a total of 800 marks. Candidates are awarded scores based on their performance in the CUET exam. The process to calculate the CUET marks vs percentile 2024 will be explained in a step by step process in this article. Students can know how to calculate their marks obtained in the exam. Read the complete article to know more about the marking scheme, percentile, passing marks and CUET 2024 marks vs percentile.
Candidates can check the marking scheme to calculate the CUET results 2024. Students who have appeared for the examination can calculate their estimated marks with the CUET 2024 marking scheme.
Particulars | Marking scheme |
Correct answer | +5 marks |
Incorrect answer | -1 mark |
Unattempted answer | 0 marks |
Students should follow the steps mentioned below on how to calculate marks obtained in the CUET exam 2024.
Calculate the no.of responses recorded by the candidate - Applicants must check their OMR/response sheets to calculate the marks obtained with the CUET marking scheme 2024.
Marks awarded for correct answers - According to the CUET 2024 marking scheme, the NTA will award +5 marks for every correct answer.
Marks awarded for incorrect answers - The NTA will award -1 mark for every incorrect answer recorded in the response sheet.
Calculating the CUET scores 2024 - Students should calculate their marks based on the marking scheme of CUET.
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CUET 2024 scores = (5 marks * no .of correct answers) - ( 1 mark * no.of incorrect answers)
Candidates who have appeared for the CUET exam 2024 should score the minimum passing marks in order to qualify for the admission process. The CUET 2024 passing marks will vary on different sections. Here are the requirements of CUET passing marks 2024 of different sections.
In Section I (Languages A and B) - students should score a minimum of 80 to 90 marks for each section - A and B.
In Section II (Domain subjects) - the minimum marks required are above 120 marks.
In Section III (General test) - candidates must score above 120 marks.
The NTA will calculate the marks achieved by the students in the examination and compare it with the other candidates who have appeared for the same exam in the similar session. The CUET percentile is calculated by dividing the difficulty level of the exam with the total number of students who appeared for the exam.
Candidates can use the below formula to convert raw score into percentile:
CUET percentile calculator = (Number of candidates who scored equal to or lower than your raw score / Total number of test takers) * 100
The CUET percentile can be calculated by multiplying the marks obtained by the candidate with 100 and dividing the total amount with 200. It will produce the CUET 2024 percentile of the individual candidate.
(Marks obtained / total marks) * 100
Example - If a student has obtained 120 marks in the CUET 2024 exam, the CUET percentile will be calculated and shown below.
Marks obtained = 120;
Total marks = 200
CUET Percentile = (120/200) * 100 = 60%
The candidate has secured 70% in the CUET exam 2024.
The NTA will calculate the CUET 2024 marks obtained by the student with other students using the percentile method. In this method, the NTA will calculate the percentiles rather than the raw scores of students. Students can check the table given below of previous year’s marks vs percentile to estimate their marks in the CUET 2024.
Candidates can estimate their CUET percentile and marks by going through the previous year’s data of CUET marks vs percentile.
Marks Range | Percentile |
200 - 188 | 100 |
187 - 170 | 99 |
169 - 150 | 98 - 97 |
149 - 130 | 96 - 95 |
129 - 110 | 94 - 93 |
109 - 90 | 92 - 90 |
89 - 80 | 89 - 84 |
79 - 70 | 83 - 80 |
69 - 60 | 79 - 75 |
59 - 50 | 74 - 70 |
49 - 40 | 69 - 55 |
39 - 20 | 54 - 30 |
Note: The CUET 2024 marks vs percentile will be varied based on several factors. Candidates can check the table given above for the previous year’s data.
Frequently Asked Questions (FAQs)
Calculate the marks obtained by the candidate with the total marks and multiply it with 100 to get the CUET 2024 percentile.
(Marks obtained / total marks) * 100
Marks obtained in the exam is 180, and the total marks of the exam is 200.
CUET percentile = 180/200 * 100 = 90%
Marks obtained in the exam is 140, and the total marks of the exam is 200.
CUET percentile = 140/200 * 100 = 70%
If a student scored 70%, then the marks can be calculated by multiplying the percentile with the total marks and then dividing the total with 100.
CUET marks = (percentile obtained * total marks) / 100
CUET marks = (70 * 200) / 100 = 140
The candidate has secured 140 marks out of 200 in the CUET exam 2024.
On Question asked by student community
Hello,
Yes, you can get a reservation to study B Tech. through cuet exam as per your category. It is partially dependent on the university you will get admission.
Thank You.
The top government colleges offering B.Tech admission through the CUET exam in Delhi primarily include institutions under Guru Gobind Singh Indraprastha University (GGSIPU) and specific colleges within the University of Delhi (DU).
Here are the key government colleges that accept CUET scores for B.Tech:
Cluster Innovation Centre (CIC), University of Delhi: Offers B.Tech. in Information Technology & Mathematical Innovation, with admission based strictly on CUET scores, and it is known for its low fee structure.
Faculty of Technology, University of Delhi (DU): DU has also started admitting students to its B.Tech programs (like Computer Engineering, Electrical Engineering, etc.) via the CUET (and usually JEE Main).
Guru Gobind Singh Indraprastha University (GGSIPU): While GGSIPU primarily uses JEE Main scores, some of its programs in the main campus and the GGSIPU East Delhi Campus accept CUET scores for admission, particularly for certain specializations.
It is important to check the specific course eligibility for each university, as highly ranked institutions in Delhi like Netaji Subhas University of Technology (NSUT) and Delhi Technological University (DTU) rely more heavily on high JEE Main ranks for admission through JAC Delhi counselling, rather than CUET alone.
This video provides information on the best B.Tech colleges that accept CUET scores. (https://www.youtube.com/watch?v=sshnjeDMTN8) https://engineering.careers360.com/articles/cuet-btech-government-college-list
Hello,
Yes, the Common University Entrance Test (CUET) is the entrance exam for BSc Biotechnology at Delhi University (DU). Admission requires a strong performance in the CUET, and eligibility also depends on meeting specific subject requirements in Class 12, such as physics, chemistry, and biology/biotechnology/biochemistry.
I hope it will clear your query!!
Hi! CUET UG 2025 will be conducted in May–June 2025 in computer-based mode across multiple shifts. Registration is open from March 1–22, 2025, with corrections allowed from March 24–26. It is for students completing Class 12 or equivalent, and eligibility may vary by university. The exam has Language, Domain-Specific Subjects, and General Test sections. Admit cards will be released in May, and results are expected in June 2025, followed by university counseling.
https://university.careers360.com/exams/cuet-ug
https://university.careers360.com/exams/cuet-ug/articles
If you mean that you are in your second year of a BA program and want to appear for CUET PG 2026, then yes you can take the exam. However, you will not be eligible for admission that year because you are still in your second year, and CUET PG scores are valid only for the immediately following academic session.
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