JNUEE application form submission last date extended to May 31.
JNU Result 2020 - National Test Agency will announce the JNU 2020 result at nta.ac.in after the commencement of entrance examination. The candidates who will appear in the online examination will get the facility to check their result of JNU 2020 by entering their login credentials. The JNU result 2020 contains details such as marks and the qualifying status of the candidates who appeared in the online examination for JNU admission 2020. The result of JNU 2020 will be released in the form of a scorecard which the candidates can download by logging into their student portals.Latest: To check JNU semester results, click hereLast date of filling and submitting JNU application form 2020 extended to May 31
JNUEE is conducted by the National Test Agency (NTA) for the candidates who wish to seek admission in various UG, PG, M. Phil and Ph.D. programmes offered by the university. The examination will be conducted by NTA in online mode.
Events
Dates
Conduct of JNUEE 2020
To be notified
Release of JNUEE 2020 Question Paper and Answer Key
JNU Final Answer Key 2020
JNU entrance exam result (PG)
JNU 2020 Merit list for Viva-Voce based programmes
Second merit list for JNU admissions
Release of final list after registration
Counselling schedule
The JNU result 2020 will be declared in online mode. The result will be released in the form of a JNU scorecard. Checking the results online on the official website can be a little tricky as the candidates are not acquainted with the whole website. Therefore, the candidates are suggested to follow the steps to check the JNU 2020 result which is given below.
Step 1: Visit the official website of NTA.
Step 2: To check the JNU entrance exam result 2020, candidates can either click on ‘Search by Application Number’ or ‘Search by Registration Number’.
Step 3: A drop-down will appear where candidates have to select the ‘Programme of Study’ from the menu provided.
Step 4: Choose the ‘field of study’.
Step 5: Enter the Application and/or Registration Number.
Step 6: Click on ‘Search’.
The result showing the marks and ranks scored by the candidate will appear in a new tab.
There are certain details that are mentioned on the candidate’s JNU 2020 result which the candidates must look out for. The details are given as follows-
Candidate's name
Roll Number
Gender
Category of Candidate
NTA Score
Marks scored in each section
Father's Name
Mother's Name
Date of Birth
National Testing Agency has introduced a process of standardizing procedure on the basis of percentile score in order to maintain equivalence among various question papers and the difficulty level of question paper in each session. The score obtained by the candidates, after considering the relative performance of all examinees, who will appear in the examination for each session is the NTA score. JNU 2020 result shows the percentage of candidates who have scored equal or below to a pre-set percentile in the entrance exam of JNU. The marks scored by the candidates in the entrance examination are transformed into a scale ranging from 100 to 0 for each session comprises of NTA score. Then the merit lists carrying the rank of the candidates are made on the basis of percentile score of JNUEE result 2020.
Step 1 - Raw Score Calculation
The initial score of JNU Result 2020 is calculated on the basis of the normal marking scheme of the examination. For every correct answer, candidates are awarded 4 marks, whereas for every incorrect answer one mark is deducted.
Step 2 - Conversion of Raw Score into NTA Score
NTA score = 100*Number of candidates appeared in the exam with the initial score equal to or less than the candidate/ Total number of candidates appeared in the exam.
National Test Agency will release the JNU 2020 Answer Key in online mode. Before releasing the final answer key, the agency will release the provisional one. The candidates will be given a facility to raise an objection against the provisional JNU answer key 2020 before the limited time period that will be notified by the agency. It must also be noted that the candidates will have to pay an extra Rs. 1000 for raising the objection. The final answer key of JNU 2020 will be released by NTA is the objections raised by the candidates are found valid. Candidates can also check their recorded responses before the declaration of result.
Candidates will have to download the scorecard of JNU 2020 in online mode. NTA will release the result in the form of a JNU 2020 scorecard. The scorecards will be released for both the UG and PG programmes. Candidates are suggested to download and keep multiple copies of their scorecards of JNU 2020 for further admission procedures including counselling, interview, etc.
The result of JNU 2020 will be announced in the form of a scorecard. There are certain details that will be printed on the scorecard which a candidate must keep an eye on. Such details are mentioned below
Name of the candidate
Registration Number
Total Marks Secured
Application Number
Course
NTA will release the JNU 2020 merit list after it has declared the result in online mode. The result of JNU 2020 contains the name of the candidates who are shortlisted for further admission procedure. The selected candidates have to register for the remaining admission procedure. If the candidates miss out the JNU admission procedure after the declaration of merit list, they will be made to forfeit his or her seat. The JNU merit list 2020 differs as per the categories of the candidates.
There are some seats reserved in the total seats offered to the candidates. Each category has its own reservation criteria which include some of the seats reserved especially for their category. The seats reserved for each category is given in the table below.
Category
Seats Reserved
SC
15%
ST
7.5%
OBC
27%
CoW
5%
Candidates from J&K
3 seats for B.A and 2 seats for M.A/M.Sc
JNU 2020 cutoff is the minimum marks required by the candidates, who appeared in JNUET 2020, to qualify for admission to various UG and PG programmes offered by the university. NTA will release two cutoff lists containing the cutoff marks. It must be noted that the cutoff of JNU will differ as per the different categories and different courses.
Courses
UR
PH
EWS
FN
M.A. in Persian
30
‐‐
28
M.A. in Arabic
82
56
79
31
70
M.A. in Hindi
94
81
83
91
M.A. in English
80
68
73
67
74
51
M.A. in Urdu
25
49
63
53
M.A. In Economics
60
57
72
34
M.A. in Economics (with specialization in World Economics)
93
71
75
85
39
M.A. in Korean
65
62
46
M.A. in Philosophy
86
78
42
B.A.(Hons.) 1st year in Korean
48
B.A.(Hons.) 1st year in Spanish
69
58
64
SUBJECT NAME
80.000
28.000
62.000
52.000
M.A. in Russian
56.000
M.A. in Spanish
M.A. in Linguistics
79.000
67.000
47.000
71.000
M.A. in Arts and Aesthetics
70.000
49.000
B.A.(Hons.) 1st year in Persian
67.500
B.A.(Hons.) 1st year in Arabic
69.000
B.A.(Hons.) 1st year in Japanese
43.000
ii. B.A.(Hons.) 1st year in Pashto
74.500
Answer:
JNU score include the marks obtained by the candidates on the basis of general marking scheme, according to the JNU’s marking scheme. Whereas, NTA Score is the percentile score obtained by the candidate in JNU result after the process of normalization by the agency.
No, the university or the conducting body will not be sending the result via post/courier. The candidates have to login to their Students’ Portal with the help of login credentials to check their result.
The result will be announced in online mode.
The result of JNU 2020 will include details such as candidate’s names, enrollment number, the scores acquired by them.
The candidates have to visit the official website of JNU. The result can be checked by entering the login credentials to their Student’s Portal.
The qualifying candidates will be able to apply for JNU counselling 2020. The candidates will have to apply for the counselling process in online mode.
The result will be valid for one year. The authority conducted the JNU entrance test every year for candidates who wish to seek admission in various UG and PG programmes.
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Hello student admission in Jawahar Lal Nehru University for electronics and communication B.tech course is through Jee main paper 1 entrance examination and the syllabus for Jee main paper 1 entrance examination is the whole syllabus of physics chemistry and mathematics of class 11 and 12.
Eligibility - candidates must passed or appearing class appearing class 12 with physics chemistry and mathematics with minimum 75 percent marks aggregate from a recognized board.
For more updates refer to the link mentioned below - https://www.google.com/amp/s/www.careers360.com/university/jawaharlal-nehru-university-new-delhi/amp
Feel free to comment if you have any doubt
Good luck
Hello,
There are a lot of courses offered by JNU.The eligibility criteria is different for different courses.To appear for JNUEE the candidates should meet the eligibility criteria mentioned for the particular course.For BA Hons courses the eligibility criteria is to have completed 10+2 with a minimum of 45% marks.Visit the link below to know more about the eligibility criteria for various courses : https://university.careers360.com/articles/jnu-eligibility-criteria
Hello Aspirant,
The Jawaharlal Nehru University Entrance Exam (JNUEE) is conducted to offer admission to aspirants in various undergraduate and postgraduate programmes offered by the university. The university offers a wide range of courses and the eligibility criteria differs for each course. You are kindly requested to check the eligibility criteria for various courses in the given link:
https://university.careers360.com/articles/jnu-eligibility-criteria
Good Luck
Hello
Doing bsc after 12th boards is good decision but it has to be bold enough as you must have a keen interest in the core subjects like physics , chemistry, etc . It must also be clear that scope and opportunities in this field are also wide spread . At last I will tell you that you can surely opt for this field .
hi,
jnu pg entrance test will be an mcq tyoe entrance test, duration will be 4 hours,
JNU paper for M.Sc. entrance paper has two parts.
The first part has questions from Science and Mathematics (based on 10+2)
Second part of JNU paper for MSc. courses carries questions from Physics, Botany, Geology, Zoology, Chemistry and Mathematics of B.Sc. level.
so you need to study throughly you ug courses questions related with your msc streams,
some of the books you should follow,
A Complete Resource Manual M.Sc Mathematics Entrance examination by suraj singh , rashmi gupta
IIT JAM (Joint Admission Test for M.Sc.) 2020 - Mathematics by gkp publications.
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