With an 80 percentile in JEE Mains and an interest in Aeronautical Engineering, you may have options in colleges offering this specialized course. In India, institutes like Embry-Riddle Aeronautical University, Indian Institute of Space Science and Technology (IIST), and  MIT

For more details you can visit the link given below

https://engineering.careers360.com/articles/jee-main

Dear aspirant !

Hope you are doing good !

To get the model set of Bengali 10th jharkhand board ,you need to visit the link given below ;-

On the link you will get the sample paper which will definitely boost your marks in the main examination of yours and you will get good marks . Solve these papers with full concentration and understanding of concept is very easy ..

https://www.google.com/url?sa=t&source=web&rct=j&opi=89978449&url=https://school.careers360.com/download/sample-papers/jharkhand-board-10th-bengali-sample-paper&ved=2ahUKEwis6pPRtZKEAxXMnq8BHTaUDFAQFnoECBkQAQ&usg=AOvVaw3YrdNIrh69Ob4c7cyVB-ff .

Hope you get it !

Thank you

With an approximate 80 percentile in JEE Main 2024, you might have a chance at getting admission to Computer Science (CSE) under the OBC category at some institutions. However, top-tier colleges, especially those in Hyderabad, often have higher cutoffs. For instance, some institutes like NIT Warangal or IIIT Hyderabad typically have closing ranks above 90 percentile for CSE in the OBC category. Keep an eye on counseling updates and consider applying to a variety of colleges based on the final rank list.

For more details you can visit the link given below

https://engineering.careers360.com/articles/jee-main

Hey Varun,

Hope you're doing well.

You can get your mock questions for Manipal Entrance Test at https://engineering.careers360.com/articles/met-mock-test .

For previous year papers you can visit : https://engineering.careers360.com/articles/met-sample-papers

Hope tghis helps you.

All the best! Keep preparing.

Correct Answer: (16, 26, 31)

Solution : Given:
(3,13,18), (29, 39, 44)
Add 10 to the first number to get the second number and add 5 to the second number to get the third number –
⇒ (3,13,18)→3 + 10 = 13, 13 + 5 = 18
⇒ (29, 39, 44)→29 + 10 = 39, 39 + 5 = 44

Let's check each option –
First option: (17, 27, 42)→17 + 10 = 27, 27 + 5 = 32 ≠ 42
Second option: (25, 30, 55)→25 + 10 = 35 ≠ 30, 30 + 5 = 35 ≠ 55
Third option: (26, 30, 47)→26 + 10 = 36 ≠ 30, 30 + 5 = 35 ≠ 47
Fourth option: (16, 26, 31)→16 + 10 = 26, 26 + 5 = 31

So, only the fourth option follows the same pattern as followed by the given set of numbers. Hence, the fourth option is correct.

Correct Answer: (7, 70, 700)

Solution : Given:
(5, 50, 500); (3, 30, 300)

Multiply the first number by 10, to obtain the second number, and multiply the second number by 10, to obtain the third number –
⇒ (5, 50, 500)→5 × 10 = 50; 50 × 10 = 500
⇒ (3, 30, 300)→3 × 10 = 30; 30 × 10 = 300

Let's check the options –
First option: (11, 110, 2200)→11 × 10 = 110; 110 × 10 = 1100 ≠ 2200
Second option: (7, 70, 700)→7 × 10 = 70; 70 × 10 = 700
Third option: (14, 140, 1500)→14 × 10 = 140; 140 × 10 = 1400 ≠ 1500
Fourth option: (12, 220, 440)→12 × 10 = 120 ≠ 220; 220 × 10 = 2200 ≠ 440

So, only the second option follows the same pattern as the given set of numbers. Hence, the second option is correct. 

Correct Answer: (19, 216, 25)

Solution : Given:
(12, 125, 17); ( 8, 27, 11)

Subtract the first number from the third number, and then cube the resultant, to get the second number –
⇒ (12, 125, 17)→(17 – 12)³ = 5³ = 125
⇒ (8, 27, 11)→(11 – 8)³ = 3³ = 27

Let's check each option –
First option: (11, 32, 15)→(15 – 11)³ = 4³ = 64 ≠ 32
Second option: (19, 216, 25)→(25 – 19)³ = 6³ = 216
Third option: (17, 16, 19)→(19 – 17)³ = 2³ = 8 ≠ 16
Fourth option: (9, 216, 16)→(16 – 9)³ = 7³ = 343 ≠ 216

So, only the second option follows the same pattern as the given set of numbers. Hence, the second option is correct.